You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of:
(a) potassium chloride
(b) potassium nitride
(c) potassium sulphide
(d) potassium iodide

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Solution

(d) potassium iodide
Potassium iodide on reacting with lead nitrate gives yellow precipitate of lead iodide.

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Q. You are given a solution of lead nitrate. In order to obtain a yellow precipitate you should mix it with a solution of:

Lead nitrate reacts with potassium iodide to form a yellow precipitate of.

$P b (N O_{3})_{2} (a q) + 2 K C l (a q) \to 2 K N O_{3} (a q) + P b C l_{2} (s)$

When lead nitrate solution is mixed with potassium chloride solution, a precipitate of lead chloride and potassium nitrate solution are formed. This type of reaction is called _________________.

$P b (N O_{3})_{2} (a q) + 2 K C l (a q) \to 2 K N O_{3} (a q) + P b C l_{2} (s)$

When lead nitrate solution is mixed with potassium chloride solution, a precipitate of lead chloride and solution of potassium nitrate are formed. This type of reaction is called _________________.

Q. Assertion :"A golden yellow precipitate of lead iodide is formed when colourless lead nitrate solution is mixed with colourless solution of potassium iodide." So, it is a chemical change Reason: Formation of new products in the reaction with the precipitate indicates a chemical change

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You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of: (a) potassium chloride (b) potassium nitride (c) potassium sulphide (d) potassium iodide

(d) potassium iodide Potassium iodide on reacting with lead nitrate gives yellow precipitate of lead iodide.

You are given the solution of lead nitrate. In order to obtain a yellow precipitate you should mix with it a solution of:
(a) potassium chloride
(b) potassium nitride
(c) potassium sulphide
(d) potassium iodide

(d) potassium iodide
Potassium iodide on reacting with lead nitrate gives yellow precipitate of lead iodide.