Question

You are given with following materials:

1. Barium chloride solution
2. Copper sulphate solution

Identify the type of chemical reaction taking place when:

Barium chloride solution is mixed with Copper sulphate solution and a white precipitate is observed.

Answer 1

Double displacement reaction:

A chemical reaction in which one component of each of both the reacting molecules is transferred to form the products is known as a Double displacement reaction.

For example:

On mixing Silver nitrate$\left({\mathrm{AgNO}}_3\right)$ solution with Sodium chloride$\left(\mathrm{NaCl}\right)$, a curdy white precipitate of Silver chloride$\left(\mathrm{AgCl}\right)$ is formed along with Sodium nitrate$\left({\mathrm{NaNO}}_3\right)$.

${\mathrm{AgNO}}_3\left(\mathrm{aq}\right)+\mathrm{NaCl}\left(\mathrm{aq}\right)\to \mathrm{AgCl}\left(\mathrm{ppt}\right)+{\mathrm{NaNO}}_3\left(\mathrm{aq}\right)$

The given reaction of Barium chloride$\left({\mathrm{BaCl}}_2\right)$ solution with Copper sulphate$\left({\mathrm{CuSO}}_4\right)$ solution produces a white precipitate of Barium sulphate$\left({\mathrm{BaSO}}_4\right)$ is an example of a double displacement reaction.

The balanced chemical equation of the reaction is,

${\mathrm{BaCl}}_2\left(\mathrm{aq}\right)+{\mathrm{CuSO}}_4\left(\mathrm{aq}\right)\to {\mathrm{BaSO}}_4\left(\mathrm{ppt}\right)+{\mathrm{CuCl}}_2\left(\mathrm{aq}\right)$