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Combination Reaction

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Question

You are provided with the following chemicals :

NaOH, $N a_{2} C O_{3}, H_{2} O, Z n (O H)_{2}, C O_{2}, H C I, F e, H_{2}, S O_{4}, C I_{2}, Z n .$

Using the suitable chemicals from the given list only, state briefly how you would prepare :

(a) iron (III) chloride, (b) sodium sulphate,

(c) sodium zincate, (d) iron (II) sulphate,

(e) sodium chloride ?

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Solution

(a) Iron (III) Chloride: Iron chloride is formed by direct combination of elements.

$2 F e + 3 C l_{2} ⟶ 2 F e C I_{3}$

(b) Sodium sulphate: By neutralization of caustic soda with dilute sulphuric acid

$2 N a O H + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + 2 H_{2} O$

(c) Sodium zincate: By the action of metals with alkali

$Z n + 2 N a O H ⟶ N a_{2} Z n O_{2} + H_{2}$

(d) Iron (II) sulphate: Iron sulphate is prepared by the action of dilute acid on an active metal.

$F e + H_{2} S O_{4} ⟶ F e S O_{4} + H_{2}$

(e) Sodium chloride: By the neutralization reaction of a strong acid with a strong base

$N a O H + H C I ⟶ N a C I + H_{2} O$

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