A:
Displacement in the suspension system x=15 cm=0.15 m
As there are 4 springs in parallel to support the mass of the automobile.
The equation of restoring force for the system
F=−4kx=Mg
k is spring constant for suspension system.
k=Mg4x
k=3000×104×0.15=5×104N/m
B:
For damping factor 𝑏, the equation for displacement is given by,
x=x0e−bt/2m
Now, the amplitude of oscillation decreases by 50%,
i.e.,x=x0/2,when t=T
Time period, T=2π√mk=2π√7505×104=0.769s
Therefore,
x02=x0e−bT2m
b=2m×ln2T
b=2×750×0.6930.769=1351.58 kg/s