Question

You decided to launch a ball vertically so that a friend located $45$ m above you can catch it what is the minimum launch speed you can use?

Answer 1

$s=45$

$v=0$

$u=?$

$a=(-9.8)$

$V^2=u^2+2as$

$0=u^2+2(-9.8)\left(45\right)$

$0=u^2+(-882)882=u^2$

$29=u$