You have a test tube of length 14 cm. You blow in it and form standing waves. Can you tell the fundamental frequency of standing wave formed in the tube if it was half filled with ice. (i) for diagram 1 (ii) for diagram 2

Given v = 336 $\frac{m}{s}$

(i) - 600 Hz (ii) - 800 Hz

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(i) - 1200 Hz (ii) 600 Hz

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(i) - 800 Hz (ii) - 1200 Hz

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(i) - 600 Hz (ii) - 600 Hz

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Solution

The correct option is B
(i) - 1200 Hz (ii) 600 Hz

$λ = 4 I$ $\frac{λ}{4} = l$

$f = \frac{v}{4 l}$ $\frac{v}{f} = 4 l$

$f = \frac{336}{4 \times 7} 1200 H z$

$\frac{λ}{4} = l$

$f = \frac{v}{4 l}$

$f = \frac{336}{4 \times 14} 600 H z$

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You have a test tube of length 14 cm. You blow in it and form standing waves. Can you tell the fundamental frequency of standing wave formed in the tube if it was half filled with ice. (i) for diagram 1 (ii) for diagram 2

Given v = 336 $\frac{m}{s}$

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(i) ? (ii) ?

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You have a test tube of length 14 cm. You blow in it and form standing waves. Can you tell the fundamental frequency of standing wave formed in the tube if it was half filled with ice. (i) for diagram 1 (ii) for diagram 2 Given v = 336 ms

The correct option is B (i) - 1200 Hz (ii) 600 Hz λ = 4I λ4 = l f = v4l vf = 4l f = 3364 × 7 1200 Hz λ4 = l f = v4l f = 3364 × 14 600 Hz

You have a test tube of length 14 cm. You blow in it and form standing waves. Can you tell the fundamental frequency of standing wave formed in the tube if it was half filled with ice. (i) for diagram 1 (ii) for diagram 2

Given v = 336 $\frac{m}{s}$

The correct option is B
(i) - 1200 Hz (ii) 600 Hz

$λ = 4 I$ $\frac{λ}{4} = l$

$f = \frac{v}{4 l}$ $\frac{v}{f} = 4 l$

$f = \frac{336}{4 \times 7} 1200 H z$

$\frac{λ}{4} = l$

$f = \frac{v}{4 l}$

$f = \frac{336}{4 \times 14} 600 H z$