You have studied in Class IX that a median of a triangle divides it into two triangles of equal areas. Verify this result for ΔABC whose vertices are A (4, − 6), B (3, − 2) and C (5, 2)

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Solution

Let the vertices of the triangle be A (4, −6), B (3, −2), and C (5, 2).

Let D be the mid-point of side BC of ΔABC. Therefore, AD is the median in ΔABC.

However, area cannot be negative. Therefore, area of ΔABD is 3 square units.

However, area cannot be negative. Therefore, area of ΔADC is 3 square units.

Clearly, median AD has divided ΔABC in two triangles of equal areas.

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Q. You have studied in Class IX, that a median of a triangle divides it into two triangles of equal areas. Verify this result for

△ A B C

whose vertices are

A (4, - 6), B (3, - 2)

and

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Q. Question 5
You have studied in Class IX that a median of a triangle divides it into two triangles of equal areas. Verify this result for

Δ

ABC whose vertices are A (4, - 6), B (3, - 2) and C (5, 2).

Q. For ∆ABC, whose vertices are A(4, −6), B(3, −2) and C(5, 2), verify that a median of the triangle divides it into two triangles of equal areas.

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△ A B C

whose vertices are

A (4, - 6) B (3, - 2) C (5, 2)

If A (4, –6), B (3, –2) and C (5, 2) are the vertices of triangle ABC, then verify the fact that a median of a triangle ABC divides it into two triangle of equal areas

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