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Elevation in Boiling Point

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Question

You have the following salts on your table in a lab. $K I, H g I_{2}, N a O H, N H_{4} O H, S n C l_{2}$

(a)Salts to prepare Nassler's reagent are $K I + H g l_{2} + N a O H$
(b) Above reagent is used to identify $N H_{4}^{+}$ ion.

Both (a) and (b) are true

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Only (a) is true

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Only (b) is true

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None of the above

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Solution

The correct option is A Both (a) and (b) are true
(a) Nessler's reagent can be prepared by using $K I, H g I_{2}, a n d N a O H$
or $K I (e x c e s s), H g C l_{2} a n d N a O H$
(b)Nessler's reagent is used to identify $N H_{4}^{+}$ ions.
(c) $2 K_{2} H g I_{4} + 4 K O H + N H_{4} C l \to H g_{2} N H_{2} O I b r o w n p r e c i p i t a t e + 7 K I + K C l + 3 H_{2} O$

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Similar questions

You are provided with two reagent bottles marked A and B. One contains $N H_{4} O H$ solution and the other contains NaOH solution. How will you identify them by a chemical test ?

{H g C l}_{2} + e x c e s s o f K I ⟶ (A) {N H}_{3} / N a O H - --------- \to (B) .

(A) and (B) respectively are:

Q. Two coloured salt solutions of two metals

A

and

B

gave precipitates with

N a O H

and

{N H}_{4} O H

. The oxidation states of salts metal

A

and

B

are same. On further addition of

{N H}_{4} O H

, the precipitate disappears, in the case of

B

. There is no such change in the case of '

A

' either with

N a O H

{N H}_{4} O H

. Identify

A

and

B

. Give necessary equations :

C H_{3} C O O H A - ------- \to C H_{3} C O C l B - -------- \to C H_{3} C H O

Identify the reagents

A

and

B

in the above reactions:

Q. Reagent (A) and (B) in the above reaction are:

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You have the following salts on your table in a lab. KI,HgI2,NaOH,NH4OH,SnCl2(a)Salts to prepare Nassler's reagent are KI+Hgl2+NaOH(b) Above reagent is used to identify NH+4 ion.

The correct option is A Both (a) and (b) are true(a) Nessler's reagent can be prepared by using KI,HgI2,andNaOHor KI(excess),HgCl2andNaOH(b)Nessler's reagent is used to identify NH+4 ions.(c) 2K2HgI4+4KOH+NH4Cl→Hg2NH2OIbrownprecipitate+7KI+KCl+3H2O

You have the following salts on your table in a lab. $K I, H g I_{2}, N a O H, N H_{4} O H, S n C l_{2}$

(a)Salts to prepare Nassler's reagent are $K I + H g l_{2} + N a O H$
(b) Above reagent is used to identify $N H_{4}^{+}$ ion.