You have three resistors of values $2 Ω, 3 Ω$ and $5 Ω$ . How will you join them so that the total resistance is more than $7 Ω$ ? Calculate the equivalent resistance.

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Solution

In order to get more than $7 Ω$ resistance from three resistors $2 Ω, 3 Ω$ and $5 Ω$ , we need to connect them in series as shown in the diagram.
Equivalent resistance in series combination is given by $R_{e q} = R_{1} + R_{2} + R_{3}$
$⟹ R_{e q} = 2 + 3 + 5 = 10 Ω$ (which is greater than $7 Ω$ )

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