Question

You have three resistors of values $2\Omega ,3\Omega$, and $5\Omega$. If they are in parallel ,then the total resistance is :

• A. $0.97\Omega$
• B. $2\Omega$
• C. $10\Omega$
• D. $3\Omega$

Answer 1

The correct option is A $0.97\Omega$

Components connected in parallel are connected so the same voltage is applied to each component. In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through each component. In parallel circuits, each light has its own circuit, so all or one light could be burned out, and the last one will still function. A circuit composed solely of components connected in parallel is known as a parallel circuit.
To find the total resistance of all components, the reciprocals of the resistances of each component is added and the reciprocal of the sum is taken. Total resistance will always be less than the value of the smallest resistance That is, $\frac{1}{R_{total}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4}thatis,R={R_{total}}^{-1}$.
In this case, we have three resistors of values 2 ohms, 3 ohms and 5 ohms. For the resistance to be less than 1 ohm, the resistors should be connected in parallel.
Therefore, $\frac{1}{R_{total}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{5}=\frac{1}{1.03}=0.97\Omega$.
Hence, the resistors are connected in parallel and their equivalent resistance is 0.97 ohms.