Question

You have to show that $\Delta AMP\cong \Delta AMQ$. In the following proof, supply the missing reasons:
$\begin{array}{cc}Steps& Reasons\\ i)PM=QM& \left(i\right)\\ ii)\angle PMA=\angle QMA& \left(ii\right)\\ iii)AM=AM& \left(iii\right)\\ iv)\Delta AMP\cong \Delta AMQ& \left(iv\right)\end{array}$

Answer 1

$\begin{array}{cc}Steps& Reasons\\ i)PM=QM& \left(i\right)Given\\ ii)\angle PMA=\angle QMA& \left(ii\right)Given\\ iii)AM=AM& \left(iii\right)Common\\ iv)\Delta AMP\cong \Delta AMQ& \left(iv\right)SAScongruencerule\end{array}$