You spin a spinner that has 8 equal-sized sections numbered 1 to 8. Find the theoretical probability of landing on the given section(s) of the spinner.
(i) section 1 (ii) odd-numbered section (iii) a section whose number is a power of 2. [4 MARKS]

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Solution

part(i): 1 Mark
part(ii) and part(iii): 1.5 Marks each

Since the sections have equal size, each section is equally probable.
The probability of falling on each section is, therefore, $\frac{1}{8}$ .

(i) Hence, probability of falling on section 1 is $\frac{1}{8}$ .

(ii) There are four odd numbered sections. Hence, probability is $P (o d d n u m b e r e d s e c t i o n) = \frac{4}{8}$ = $\frac{1}{2}$ .

(iii) There are 3 numbers here which are powers of two, namely 2, 4 and 8. Hence, the required probability = $P (s e c t i o n w h o s e n u m b e r i s a p o w e r o f 2) = \frac{3}{8}$ .

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