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Fringe Width in YDSE

Young's doubl...

Question

Young's double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe widths recorded are $β_{G}$ , $β_{R}$ , $β_{B}$ respectively. Then,

β_{G}

β_{B}

β_{R}

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β_{B}

β_{G}

β_{R}

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β_{R}

β_{B}

β_{G}

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β_{R}

β_{G}

β_{B}

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Solution

The correct option is D $β_{R}$ > $β_{G}$ > $β_{B}$
we have
$β = \frac{λ d}{D}$
So, if $λ_{R} > λ_{G} > λ_{B}$ then $β_{R} > β_{G} > β_{B}$
Answer is option $(D)$

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Young's double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe widths recorded are βG, βR, βB respectively. Then,

The correct option is D βR > βG > βBwe have β=λdDSo, if λR>λG>λB then βR>βG>βBAnswer is option (D)

Young's double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe widths recorded are $β_{G}$ , $β_{R}$ , $β_{B}$ respectively. Then,

The correct option is D $β_{R}$ > $β_{G}$ > $β_{B}$
we have
$β = \frac{λ d}{D}$
So, if $λ_{R} > λ_{G} > λ_{B}$ then $β_{R} > β_{G} > β_{B}$
Answer is option $(D)$