Young-s modulus of rubber is 104 N-m2 and area of cross section is 2 cm-2- If force of 2- 105 dyn is applied along its length- then its initial l becomes-

The correct option is D 2l l = FlaY l = 2× 10^5× 10^ 5× 12× 10^ 4× 10^4 or l = 1 So, new length is 2l . ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Young's Modulus of Elasticity

Young's modul...

Question

Young's modulus of rubber is $10^{4} N / m^{2}$ and area of cross section is $2 c m^{- 2}$ . If force of $2 \times 10^{5}$ dyn is applied along its length, then its initial $l$ becomes.

3 l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $2 l$
$△ l = \frac{F l}{a Y}$
$△ l = \frac{2 \times 10^{5} \times 10^{- 5} \times 1}{2 \times 10^{- 4} \times 10^{4}}$ or $△ l = 1$
So, new length is $2 l$ .

Suggest Corrections

Similar questions

Q. Young's modulus of rubber is

10^{4}

/ m^{2}

and area of cross-section is

2

c m^{2}

. If force of

2 \times 10^{5}

dyne is applied along its length, then its final length becomes.

Q. A tensile force of

2 \times 10^{3} N

doubles the length of a rubber band pf cross-sectional area

2 \times 10^{- 4} m^{2}

. The Young's modulus of elasticity of the rubber band is

Q. An Indian rubber cord

L m

long and area of cross-section

A m^{2}

is suspended vertically. Density of rubber is

D {kg/m}^{3}

and Young's modulus of rubber is

E {N/m}^{3} .

If the wire extends by

l m

under its own weight, then extension

l

Q. The area of cross section of a steel wire of Young's modulus

Y = 2.0 \times 10^{11} {N/m}^{2}

0.1 {cm}^{2}

. Find the force required to double its length.
(Assume area of cross section remains same)

Q. An Indian rubber cord

L

metre long and area of cross-section

A

meter

^{2}

is suspended vertically. Density of rubber is

ρ k g /

meter

^{3}

and Young's modulus of rubber is

Y

Newton/metre

^{2}

. If the cord extends by

l

metre under its own weight, then extension

l

is:

Join BYJU'S Learning Program

Young's modulus of rubber is 104N/m2 and area of cross section is 2 cm−2. If force of 2×105 dyn is applied along its length, then its initial l becomes.

The correct option is D 2l△l=FlaY△l=2×105×10−5×12×10−4×104 or △l=1So, new length is 2l.

Young's modulus of rubber is $10^{4} N / m^{2}$ and area of cross section is $2 c m^{- 2}$ . If force of $2 \times 10^{5}$ dyn is applied along its length, then its initial $l$ becomes.

The correct option is D $2 l$
$△ l = \frac{F l}{a Y}$
$△ l = \frac{2 \times 10^{5} \times 10^{- 5} \times 1}{2 \times 10^{- 4} \times 10^{4}}$ or $△ l = 1$
So, new length is $2 l$ .