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Byju's Answer
Other
Quantitative Aptitude
Solving Inequalities
|Z1|=2 and ...
Question
|
Z
1
|
=
2
and
|
Z
2
−
−
6
−
8
i
=
4
|
, then the maximum distance between
Z
1
and
Z
2
is:
A
10
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B
6
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C
2
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D
2
√
41
−
2
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Solution
The correct option is
D
2
√
41
−
2
Z
1
−
6
−
8
i
=
4
x
+
i
y
−
6
−
8
i
=
4
x
−
6
+
i
(
y
−
8
)
=
4
x
=
10
,
y
=
8
Z
2
=
10
+
8
i
|
Z
2
|
=
√
10
2
+
8
i
2
=
2
√
41
|
Z
2
−
Z
1
|
≥
|
|
Z
2
|
−
|
Z
1
|
|
⟹
2
√
41
−
2
Suggest Corrections
0
Similar questions
Q.
|
Z
1
|
=
2
and
|
Z
2
−
6
−
8
i
|
=
4
, then the minimum distance between
Z
1
and
Z
2
is:
Q.
If we plot
|
Z
1
|
=
2
and
|
Z
2
−
6
−
8
i
|
=
4
, on the argand plane, the locus of
Z
1
and
Z
2
are
Q.
|
Z
1
−
3
−
4
i
|
=
2
and
|
Z
2
−
3
−
4
i
|
=
5
, then the maximum distance between the
Z
1
and
Z
2
is
Q.
Consider the complex number
z
1
and
z
2
satisfying the relation
|
z
1
+
z
2
|
2
=
|
z
1
|
2
+
|
z
2
|
2
, then the p
ossible difference between the argument of
z
1
and
z
2
is,
Q.
If
z
1
and
z
2
are two complex numbers, then prove that
|
z
1
|
+
|
z
2
|
=
∣
∣
∣
z
1
+
z
2
2
+
√
z
1
z
2
∣
∣
∣
+
∣
∣
∣
z
1
+
z
2
2
−
√
z
1
z
2
∣
∣
∣
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