Z1-4-3i- z2-1-2i then z1-z2z1-z2-

The correct option is B 10 z = (z_1+z_2)=(4 3i)+( 1+2i)=(3 i) (z̅_̅1̅+z̅_̅2̅)=4+3i+ 1 2i=3+i=z̅ ∴ z×z̅=|z|^2=(√( 9+1))^2=10 ...

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Properties of Conjugate of a Complex Number

z1=4-3i, z2=-...

Question

$z_{1} = 4 - 3 i, z_{2} = - 1 + 2 i$ then

$(z_{1} + z_{2}) (_{1} +_{2}) =$

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z_{1}

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