2
Question
Factorise: z−7+7xy−xyz
Factorise: z−7+7xy−xyz
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Solution
z−7+7xy−xyz
=z−7+xy(7−z)
=−7+z+xy(7−z) [Taking xy as common]
=−1(7−z)+xy(7−z)
=(7−z)(−1+xy) [Taking (7−z) as common]
=(7−z)(xy−1)
Therefore,
z−7+7xy−xyz=(7−z)(xy−1)
z−7+7xy−xyz
=z−7+xy(7−z)
=−7+z+xy(7−z) [Taking xy as common]
=−1(7−z)+xy(7−z)
=(7−z)(−1+xy) [Taking (7−z) as common]
=(7−z)(xy−1)
Therefore,
z−7+7xy−xyz=(7−z)(xy−1)
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