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Question

Factorise: z7+7xyxyz

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Solution

z7+7xyxyz

=z7+xy(7z)

=7+z+xy(7z) [Taking xy as common]

=1(7z)+xy(7z)

=(7z)(1+xy) [Taking (7z) as common]

=(7z)(xy1)

Therefore,
z7+7xyxyz=(7z)(xy1)


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