(z+a)(¯z+a) , where a is real, is equivalent to
|z-a|
None of these
As we know if a is real, then a = ¯a
∴ (z+a)(¯z+a)=(z+a)(¯z+¯a)=(z+a)¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(z+a)=|z+a|2
( z + a ) ( ¯¯¯z+a) , where a is real , is equivalent to :