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Byju's Answer
Standard XII
Chemistry
Variable Oxidation States
Zeff for 4s e...
Question
Z
e
f
f
for 4s electron in
30
Z
n
is
:
A
1.65
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B
4
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C
12.85
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D
4.35
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Solution
The correct option is
D
4.35
30
Z
n
−
1
s
2
,
2
s
2
2
p
6
,
3
s
2
3
p
6
,
3
d
10
,
4
s
2
σ
=
0.35
×
1
+
18
×
0.85
+
10
×
1
=
25.65
⇒
Z
e
f
f
=
30
−
25.65
=
4.35
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0
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