Question

z-transform of Then the value of $x\left(\infty \right)$ ___

$x\left(n\right)isX\left(z\right)=\frac{z(8z-7)}{4z^2-7z+3}$

• A. 4

Answer 1

The correct option is A 4
X(z) has pole at $Z=1,\frac{3}{4}$

$\therefore$ From final value theorem

$\underset{n\to \infty }{\text{lim}}x\left(n\right)=\underset{n\to \infty }{\text{lim}}(z-1).X\left(z\right)$

Final value is = $\text{lim}(z\to 1)\frac{z(8z-7)}{(z-1)(z-\frac{3}{4})}=4$