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Byju's Answer
Standard XII
Mathematics
Sum of Infinite Terms
z1 and z2 are...
Question
z1 and z2 are two complex numbers such that Iz1I=Iz2I and arg (z1 ) + arg (z 2 ) = π, then show that z1 = − conjugate z2
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Solution
Dear student
l
e
t
z
1
=
x
+
i
y
a
n
d
z
2
=
a
+
i
b
z
1
=
z
2
x
2
+
y
2
=
a
2
+
b
2
x
2
+
y
2
=
a
2
+
b
2
-
-
-
(
1
)
a
r
g
(
z
1
)
+
a
r
g
(
z
2
)
=
π
tan
(
arg
(
z
1
)
+
arg
(
z
2
)
)
=
tanπ
=
0
tan
(
arg
(
z
1
)
)
+
tanarg
(
z
2
)
=
0
y
x
+
b
a
=
0
y
=
-
bx
a
putting
in
(
1
)
,
we
get
x
2
+
y
2
=
a
2
+
b
2
x
2
+
b
2
x
2
a
2
=
a
2
+
b
2
x
2
=
a
2
x
=
±
a
y
=
-
b
or
+
b
so
,
z
1
=
a
-
ib
,
z
2
=
a
+
ib
,
or
z
1
=
-
a
+
ib
,
z
2
=
a
+
ib
but
in
the
case
of
z
1
=
a
-
ib
,
z
2
=
a
+
ib
,
arg
(
z
1
)
+
arg
(
z
2
)
=
0
So
,
z
1
=
-
a
+
ib
=
-
(
a
-
ib
)
=
-
conjugatez
2
Regards
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0
Similar questions
Q.
If
z
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and arg
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Q.
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Q.
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