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Zeolites

Zeolites are ...

Question

Zeolites are a microporous catalyst. The general formula of a zeolite may be given as:

M_{x / n} [(A l O_{2})_{x} (S i O_{2})_{y}] . m H_{2} O

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M [(A l O_{2})_{x}] . m H_{2} O

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M_{x} [(A l O_{2})_{x} (S i O_{2})_{y}]

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M_{x} [(S i O_{2})_{y}] . m H_{2} O

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Solution

The correct option is A $M_{x / n} [(A l O_{2})_{x} (S i O_{2})_{y}] . m H_{2} O$
Zeolites are microporous catalyst. They are the silicates of the aluminium.
Formula of Zeolites may be given as :
$M_{x / n} [(A l O_{2})_{x} (S i O_{2}) y] . m H_{2} O$

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Similar questions

M X

E_{1}

\to

M^{+} + X^{-}

M^{+} + n H_{2} O

\to

[M (H_{2} O)_{n}]^{+}

E_{2}

X^{-} + m H_{2} O

\to

[X (H_{2} O)_{m}]^{-}

E_{3}

E_{1}

E_{2}

E_{3}

M (H_{2}) \times (M (O_{2}) / M (H_{2} O))

M (H_{2})

H_{2}

M (O_{2})

O_{2}

M (H_{2} O)

H_{2} O

H_{2} O (l, 323 K) \to H_{2} O (g, 423 K)

C_{v, m} (H_{2} O, 1) = 75.0 J K^{- 1}; C_{p, m} (H_{2} O, g) = 33.314 J K^{- 1} m o l^{- 1}; Δ H_{v a p} at 373 K = 40.7 k J / m o l

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