Question

find the zero's of polynomial $\text{P}\left(\text{x}\right)\text{=}{\text{x}}^{\text{2}}\text{-}\text{5x}\text{+}\text{6}$

Answer 1

We have, $P\left(x\right)=x^2-5x+6$
To find the zero's of this polynomial.
So, $P\left(x\right)=0$
$\Rightarrow x^2-5x+6=0$
$\Rightarrow x^2-3x-2x+6=0$
$\Rightarrow x(x-3)-2(x-3)=0$
$\Rightarrow (x-2)(x-3)=0$
$\therefore x=2,3$ are required zero's.