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Solving a Quadratic Equation by Factorization Method

Question 9 Ze...

Question

Question 9
Zero of the polynomial p(x) = 2x + 5 is

A) $- \frac{2}{5}$
B) $- \frac{5}{2}$
C) $\frac{2}{5}$
D) $\frac{5}{2}$

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Solution

The answer is B.
Given, P(x) = 2x + 5
To find zero of the polynomial, put p(x)=0.
$∴ 2 x + 5 = 0$
$\Rightarrow x = - \frac{5}{2}$
Hence, zero of the polynomial p(x) is $\frac{- 5}{2}$ .

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Similar questions

Zero of the polynomial p(x)=2x+5 is
(a) $\frac{- 2}{5}$
(b) $\frac{- 5}{2}$
(c) $\frac{2}{5}$
(d) $\frac{5}{2}$

Question 9
Zero of the polynomial p(x) = 2x + 5 is

A) $- \frac{2}{5}$
B) $- \frac{5}{2}$
C) $\frac{2}{5}$
D) $\frac{5}{2}$

Q. Zero of the polynomial p(x) = 2x + 5 is

(a)

\frac{- 2}{5}

\frac{- 5}{2}

\frac{2}{5}

\frac{5}{2}

Q. Verify that:
(i) 2 is a zero of the polynomial p(x) = (x

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2).
(ii) 2 and 9 are zeroes of the polynomial p(x) = (x

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9).
(iii) 4 and

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3 are zeroes of the polynomial p(x) = x²

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Q. Question 10
One of the zeroes of the polynomial is

2 x^{2} + 7 x - 4

A) $2$
B) $\frac{1}{2}$
C) $- \frac{1}{2}$
D) $- 2$

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Solving a Quadratic Equation by Factorization Method

Standard X Mathematics

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