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Standard X

Mathematics

Solving a Quadratic Equation by Factorization Method

Zeroes of pol...

Question

Zeroes of polynomial $p (x) = x^{2} - 3 x + 2$ are

3

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1

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Solution

The correct options are
B $1$
D $2$
$x^{2} - 3 x + 2 = 0$
$x^{2} - 2 x - x + 2 = 0$
$x (x - 2) - 1 (x - 2) = 0$
$(x - 1) (x - 2) = 0$
$x = 1, x = 2$

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Similar questions

Verify that
(i) 1 and 2 are the zeros of the polynomial, $p (x) = x^{2} - 3 x + 2$ .
(ii) 2 and -3 are the zeros of the polynomial, $q (x) = x^{2} + x - 6.$
(iii) 0 and 3 are the zeros of the polynomial, $r (x) = x^{2} - 3 x$ .

Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(x)=3x+1,x= $\frac{- 1}{3}$

(ii) p(x)=5x− $π$ ,x= $\frac{4}{5}$

(iii) p(x)= $x^{2}$ -1,x=1,−1

(iv) p(x)=(x+1)(x−2),x=−1,2

(v) p(x)= $x^{2}$ ,x=0

Verify whether the following are zeroes of the polynomial, indicated against them.

(i) (ii)

(iii) p(x) = x² − 1, x = 1, − 1 (iv) p(x) = (x + 1) (x − 2), x = − 1, 2

(v) p(x) = x², x = 0 (vi) p(x) = lx + m

(vii) (viii)

Q. Question 3
Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(x) = 3x + 1, x =

- \frac{1}{3}

(ii)

p (x) = 5 x - π, x = \frac{4}{5}

(iii)

p (x) = x^{2} - 1, x = 1, - 1

(iv) p(x) = (x +1) (x -2), x = - 1, 2
(v)

p (x) = x^{2}, x = 0

(vi)

p (x) = i x + m, x = - \frac{m}{i}

(vii)

p (x) = 3 x^{2} - 1, x = - \frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}

(viii)

p (x) = 2 x + 1, x = \frac{1}{2}

Q. Question 3
Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(x) = 3x + 1, x =

- \frac{1}{3}