Zeroes of x2+78x+142 are
one negative and one positive
X coefficient is positive, constant is positive and the sum of the roots is negative → both zeroes are -ve
zeroes of x2−32x−68 are
If c, d are zeroes of x2-10x-11b and a , b are zeroes of x2-10cx-11d then value of a+b+c+d= ?
Factorise by splitting the middle term: 24x 2- 65x+ 21