Zeroes of $x^{2} + 78 x + 142$ are

both positive

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both negative

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one negative and one positive

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both equal

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Solution

The correct option is B
both negative

X coefficient is positive, constant is positive and the sum of the roots is negative $\to$ both zeroes are -ve

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Similar questions

zeroes of $x^{2} - 32 x - 68$ are

x^{2} - 8 x + 15

If c, d are zeroes of x2-10x-11b and a , b are zeroes of x2-10cx-11d then value of a+b+c+d= ?

A) 1210

B)-1

C)2530

D)-11

Factorise by splitting the middle term: 24^{x 2}- 65^x+ 21

{(- \frac{x}{2} + y + \frac{1}{4})}^{2}

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