Zeros of the polynomial p (x) = $x^{2} - 2 x$ is /are

0, 2

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0, 1

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1, 2

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2, 3

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Solution

The correct option is A $0, 2$
Zeros of the polynomial $x^{2} - 2 x = p (x)$

$x^{2} - 2 x = 0$

$\Rightarrow x (x - 2) = 0$

$\Rightarrow x = 0$ or $x = 2$

$∴$ Zeros of polynomial $p (x)$ are $0$ and $2$ .

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Similar questions

Zero of the polynomial $p (x) = x^{2} + x - 6$ are
(a) 2,3
(b) -2,3
(c) 2,-3
(d) -2,-3

y = \sqrt{x}, x \in [0, 1], y = x^{2}, x \in [1, 2]

y = - x^{2} + 2 x + 4, x \in 0, 2]

s (x) = x^{2}, x = 0, 1

{0, 1, 2}

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