Zeros of the polynomial $x^{2} - 4 x - 21$ are:

3 a n d 7

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- 3 a n d 7

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3 a n d - 7

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- 3 a n d - 7

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Solution

The correct option is B $- 3 a n d 7$
Given: polynomial $x^{2} - 4 x - 21$
To find the zeroes of the polynomial
Sol:
The zeroes of the polynomial can be found by equation the polynomial to zero and finding the values of the variable.
Hence, $x^{2} - 4 x - 21 = 0$
$⟹ x^{2} - 7 x + 3 x - 21 = 0 ⟹ x (x - 7) + 3 (x - 7) = 0 ⟹ (x - 7) (x + 3) = 0$
Therefore the zeroes of the polynomial are $- 3, 7$

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