Zinc and hydrochloric acid acid react according to the followning reaction-Zn-s-2HCl-aq- -8203- gives ZnCl2-aq-H2-g-If 0-30 mol of Zn are added to HCl containing 0-52 mol of HCl- how many moles of hydrogen are produced -

Form the equation, the mole ratio of nbsp;Zn: HCl:H2 nbsp;is nbsp;1:2:1 Ratio of given amounts of Zn: HCl nbsp;is 0.3:0.52 or 0.3: 0.52 or 1: 1.73 ...

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Standard VII

Chemistry

Acids

Zinc and hydr...

Question

Zinc and hydrochloric acid acid react according to the followning reaction.
Zn(s)+2HCl(aq) gives ZnCl₂(aq)+H₂(g)
If 0.30 mol of Zn are added to HCl containing 0.52 mol of HCl, how many moles of hydrogen are produced ?

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Solution

Form the equation, the mole ratio of Zn: HCl:H₂ is 1:2:1

Ratio of given amounts of Zn: HCl is 0.3:0.52 or 0.3: 0.52 or 1: 1.73
As 1.73 is less than 2, HCl is the limiting reactant and will decide on the amount of products formed.

Moles of hydrogen gas formed = 0.52/2 = 0.26 mol

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Zinc and hydrochloric acid acid react according to the followning reaction. Zn(s)+2HCl(aq)​ gives ZnCl2(aq)+H2(g) If 0.30 mol of Zn are added to HCl containing 0.52 mol of HCl, how many moles of hydrogen are produced ?

Form the equation, the mole ratio of Zn: HCl:H2 is 1:2:1 Ratio of given amounts of Zn: HCl is 0.3:0.52 or 0.3: 0.52 or 1: 1.73 As 1.73 is less than 2, HCl is the limiting reactant and will decide on the amount of products formed. Moles of hydrogen gas formed = 0.52/2 = 0.26 mol

Zinc and hydrochloric acid acid react according to the followning reaction.
Zn(s)+2HCl(aq) gives ZnCl₂(aq)+H₂(g)
If 0.30 mol of Zn are added to HCl containing 0.52 mol of HCl, how many moles of hydrogen are produced ?

Form the equation, the mole ratio of Zn: HCl:H₂ is 1:2:1

Ratio of given amounts of Zn: HCl is 0.3:0.52 or 0.3: 0.52 or 1: 1.73
As 1.73 is less than 2, HCl is the limiting reactant and will decide on the amount of products formed.

Moles of hydrogen gas formed = 0.52/2 = 0.26 mol