Zinc sulphate contains $22.65 %$ of zinc and $43.9 %$ of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be

45.3 g

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4.53 g

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0.453 g

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453 g

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Solution

The correct option is B 4.53 g
100 g of $Z n S O$ crystals are obtained from =22.65g Zn
1g of $Z n S O$ crystals will be obtained from $= \frac{22.65}{100} g Z n$
20 g of $Z n S O$ crystals obtained from $= \frac{22.65}{100} \times 20 = 4.53 g$

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Zinc sulphate contains 22.65% of zinc and 43.9% of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be

The correct option is B 4.53 g100 g of ZnSO crystals are obtained from =22.65g Zn 1g of ZnSO crystals will be obtained from =22.65100g Zn 20 g of ZnSO crystals obtained from =22.65100×20=4.53g

Zinc sulphate contains $22.65 %$ of zinc and $43.9 %$ of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be

The correct option is B 4.53 g
100 g of $Z n S O$ crystals are obtained from =22.65g Zn
1g of $Z n S O$ crystals will be obtained from $= \frac{22.65}{100} g Z n$
20 g of $Z n S O$ crystals obtained from $= \frac{22.65}{100} \times 20 = 4.53 g$