Zinc sulphate contains $22.65 %$ of zinc and $43.9 %$ of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be

45.3 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.53 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.453 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

453 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 4.53 g
100 g of $Z n S O$ crystals are obtained from =22.65g Zn
1g of $Z n S O$ crystals will be obtained from $= \frac{22.65}{100} g Z n$
20 g of $Z n S O$ crystals obtained from $= \frac{22.65}{100} \times 20 = 4.53 g$

Suggest Corrections

Similar questions

Q. Zinc sulphate contains

22.65

% of zinc and

43.9

% of the water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce

20

g of the zinc sulphate crystals will be:

Zinc sulphate contains $22.65 %$ of zinc and $43.9 %$ of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be

Q. Zinc crystals contain 22.65% zinc and 43.9% water. If the law of constant proportions is correct,how much zinc would be required for preparation of 2.283 g of zinc sulphate ?

Q. Zinc sulphate contains 22.65% Zn and 43.9%

H_{2} O

. If the law of constant proportions is true, then the mass of zinc required to give 40 g crystals will be:

Join BYJU'S Learning Program

Zinc sulphate contains 22.65% of zinc and 43.9% of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be

The correct option is B 4.53 g100 g of ZnSO crystals are obtained from =22.65g Zn 1g of ZnSO crystals will be obtained from =22.65100g Zn 20 g of ZnSO crystals obtained from =22.65100×20=4.53g

Zinc sulphate contains $22.65 %$ of zinc and $43.9 %$ of water of crystallization. If the law of constant proportions is true, then the weight of zinc required to produce 20 g of the crystals will be

The correct option is B 4.53 g
100 g of $Z n S O$ crystals are obtained from =22.65g Zn
1g of $Z n S O$ crystals will be obtained from $= \frac{22.65}{100} g Z n$
20 g of $Z n S O$ crystals obtained from $= \frac{22.65}{100} \times 20 = 4.53 g$