Zinc sulphide crystallises with zinc ions occupying half of the tetrahedral holes in a closed packed array of sulphide ions. What is the formula of zinc sulphide?

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Solution

The zinc sulphide crystals are composed of equal number of ${Z n}^{+ 2}$ and $S^{2 -}$ ions.
Zinc ions occupy tetrahedral hole. Only half of the tetrahedral holes are occupied by ${Z n}^{+ 2}$ so that the formula of the zinc sulphide is $Z n S$ i.e. the stoichiometry of the compound is 1:1 (Only alternate tetrahedral holes are occupied by ${Z n}^{+ 2}$ )

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