Question

Zirconium phosphate $\left(Z{r}_3\right(P{O}_4{)}_4]$ dissociates into three zirconium cations of charge +4 and four phosphate anions of charge -3. If molar solubility of zirconium phosphate is denoted by $S$ and its solubility product by $K_{sp}$ then which of the following relationship between S and $K_{sp}$ is correct?

• A. $S=\left\{K_{sp}/\right(6912{)}^{\frac{1}{7}}\}$
• B. $S={\left\{K_{sp}/144\right\}}^{\frac{1}{7}}$
• C. $S={\left\{K_{sp}/6912\right\}}^{\frac{1}{7}}$
• D. $S={\left\{K_{sp}/6912\right\}}^7$

Answer 1

The correct option is C $S={\left\{K_{sp}/6912\right\}}^{\frac{1}{7}}$

$\left(Z{r}_3\right(P{O}_4{)}_4]$ $\to$ $3Z{r}^{4+}$ + $4P{O}_4^{3-}$
$3S$ $4S$

$K_{sp}=\left(4S{)}^4\right(3S{)}^3$
$S={\left(\frac{K_{sp}}{6912}\right)}^{1/7}$.