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Byju's Answer
Standard VIII
Chemistry
Physical and Chemical Properties of Hydrogen
Zn2++2e-→ Zn....
Question
Z
n
2
+
+
2
e
−
→
Z
n
. The process happening in this reaction is:
A
oxidation
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B
reduction
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C
both
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D
None of the above
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Solution
The correct option is
A
reduction
+
2
Z
n
+
2
+
2
e
−
⟶
0
Z
n
↓
↑
{Decrease in oxidation number= Reduction}
Suggest Corrections
0
Similar questions
Q.
The reaction :
Z
n
2
+
(
a
q
)
+
2
e
−
→
Z
n
(
s
)
has a electrode potential of
0.76
V
This means:
Q.
Z
n
2
+
(
a
q
)
+
2
e
→
Z
n
(
s
)
. This is
Q.
Z
n
2
+
(
a
q
)
+
2
e
→
Z
n
(
s
)
. This is
Q.
The reaction,
Z
n
2
+
(
a
q
)
+
2
e
−
→
Z
n
(
s
)
is:
Q.
Reduction potential for the following half/cell reaction are
Z
n
→
Z
n
2
+
+
2
e
−
(
E
0
(
Z
n
2
+
/
Z
n
)
=
−
0.76
V
)
F
e
→
F
e
2
+
+
2
e
−
E
0
=
0.41
V
The EMF for the cell reaction
F
e
2
+
+
Z
n
→
Z
n
2
+
+
F
e
will
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