$Z n (s) + P b {C l}_{2} (a q) ⟶ P b (s) + Z n {C l}_{2} (a q)$

In the following reaction, which element is oxidized?

Z n

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P b

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C l

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Z n^{+}

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Solution

The correct option is A $Z n$
$Z n (s) + P b {C l}_{2} (a q) ⟶ P b (s) + Z n {C l}_{2} (a q)$
$0$ $+ 2$ $0$ $+ 2$

Zinc metal is oxidised to ${Z n}^{2 +}$ .

${P b}^{2 +}$ is reduced to $P b$ .

Hence, Zn is oxidized. Thus, the correct answer is option A.

Suggest Corrections

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