You visited us 1 times! Enjoying our articles? Unlock Full Access!

SHE

Zn s / Z n 2...

Question

$Z n (s) / Z n^{2 +} (a q) ∥ C u^{2 +} (a q) / C u (s)$
${E^{0}}_{{Z n}^{2 +} / Z n} =$ $-$ 0.76V,
${E^{0}}_{{C u}^{2 +} / C u} =$ $+$ 0.34V.
Calculate ${E^{0}}_{c e l l}$ and equilibrium constant $K$ .

Open in App

Solution

$E_{c e l l}^{0} = E_{c a t h o d e}^{0} + E_{a n o d e}^{0}$
= 0.34+0.76
= 1.1 V
$E^{0} = \frac{0.0591}{n} l o g K$
1.1 = $\frac{0.0591}{2} l o g K$
K = $1.67 \times 10^{37}$

Suggest Corrections

Similar questions

E^{\circ}

C u_{(s)} + Z n_{(a q)}^{2 +} \to Z n_{(s)} + C u_{(a q)}^{2 +}

E_{C u^{2 +} / C u}^{0} = 0.34 V, E_{Z n^{2 +} / Z n}^{0} = - 0.76 V

E_{C e l l}^{o}

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

E^{\circ}

{Zn(s)|Zn}^{2 +} (aq) | | {Cu}^{2 +} (aq)|Cu(s)

1.10

25^{\circ} C

Zn(s) + {Cu}^{2 +} (aq) \to Cu(s) + {Zn}^{2 +} (aq)

1.94 \times 10^{x}

x

Z n

1.0 M

C u S O_{4}

C u^{2 +}

E_{(Z n^{2 +} | Z n)}^{0} = - 0.76 V, E_{(C u^{2 +} C u)}^{0} = - 0.34 V

E^{\circ}

Z n (s) | Z n^{2 +} 1 M (a q .) ∥ C u^{2 +} 1 M (a q .) | C u (s)

1.10 V

25^{\circ} C

Z n (s) + C u^{2 +} (a q .) ⇌ Z n^{2 +} (a q .) + C u (s)

Join BYJU'S Learning Program