wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Zn(OH)2 is an amphoteric hydroxide which is involved in the following two equilibria existing simultaneously in aqueous solution.

Zn(OH)2(s)Zn2+(aq)+2OH(aq); Ksp=1.2×1017

Zn(OH)2(s)+2OH(aq)[Zn(OH)4]2(aq); Kc=0.12

At what pH the solubility of Zn(OH)2 will be minimum?

A
pH=4.11
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
pH=6.32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
pH=7.68
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
pH=9.99
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D pH=9.99
Zn(OH)2(s)Zn+2aq+2OH(aq);Ksp

Zn(OH)2(s)+2OH[Zn(OH)4]2(aq);KC

Dissolved Zn(OH)2 is present in form of Zn+2 and [Zn(OH)24].

So, solubility s=[Zn+2]+[Zn(OH)4]2

s=Ksp[OH]2+KC[OH]2

For minimum solubility, dsd[OH]=0
2Ksp[OH]3+2KC[OH]=0

[OH]=9.8×105

pOH=4.00869

pH=14pOH=9.9913
pH=9.99

So, s=109M

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon