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Characteristics of Chemical Equilibrium

Zns +2H+aq → ...

Question

$Z n (s) + 2 H^{+} (a q) \to Z n^{2 +} (a q) + H_{2} (g)$
The above equation has an equilibrium constant $K_{e q} = 10^{25}$ . What is the value of standard EMF for the reaction.
(Given : $2.303 \frac{R T}{F} = 0.0591 V$ )

0.739 V

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1.478 V

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- 0.739 V

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- 1.478 V

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Solution

The correct option is A $0.739 V$
$Z n (s) + 2 H^{+} (a q) \to Z n^{2 +} (a q) + H_{2} (g)$
The reaction is involves $2 -$ electron change.
$∴ n = 2$
We know
$\Rightarrow E^{\circ} = \frac{R T}{n F} \times 2.303 log (k) \Rightarrow E^{\circ} = \frac{0.0591}{2} \times log 10^{25} = 0.739 V$

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