Question

$Zn\left(s\right)+2NaOH\left(aq\right)\to X+Y$. Identify the X and Y in the reaction.

• A. X:- $N{a}_{2}ZnO$ Y:- $H_{2}O$
• B. X:- $NaZnO$ Y:- $H_2$
• C. X:- $NaZnO$ Y:- $H_{2}O$
• D. X:- $N{a}_{2}Zn{O}_2$ Y:- $H_{2}O$

Answer 1

The correct option is D

X:- $N{a}_{2}Zn{O}_2$

Y:- $H_{2}O$

Zinc reacts with acids and hot concentrated alkalis to give salt and hydrogen gas.

$Zn\left(s\right)+2NaOH\left(aq\right)\to N{a}_{2}Zn{O}_2\left(aq\right)+H_2\left(g\right)$. Here zinc reacts with the concentrated alkali solution of $NaOH$ to give sodium zincate $N{a}_{2}Zn{O}_2$ and hydrogen $H_2$