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Electrolytic Cell

Zns|ZnCl 2aq...

Question

Zn(s)|ZnCl $_{2}$ (aq)|Cl $^{-}$ (aq)|Cl $_{2}$ (g)|C(s)
According to the above cell diagram the electrochemical cell described, the reaction at anode is :

\to

^{2 +}

+ 2e

^{-}

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^{2 +}

+ 2e

^{-}

\to

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_{2}

+ 2e

^{-}

\to

2Cl

^{-}

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2Cl

^{-}

\to

_{2}

+ 2e

^{-}

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Zn + Cl

_{2}

\to

ZnCl

_{2}

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Solution

The correct option is A Zn $\to$ Zn $^{2 +}$ + 2e $^{-}$
At anode, zinc is oxidized to Zn(II) ions.
$Z n \to Z n^{2 +} + 2 e^{-}$
In the cell diagram, the electrode on left hand side is anode and the electrode on right hand side is cathode. Oxidation occurs at anode and reduction occurs at cathode.

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Similar questions

Z n (s) | Z n C l_{2} (a q) | | C l^{-} (a q) | C l_{2} (g) | C (s)

Z n (s) | Z n {C l}_{2} (a q) | ∣ ∣ {C l}^{-} (a q) ∣ ∣ | {C l}_{2} (g) | C (s)

Z n | Z n^{2 +} (a q) (1.0 M) | | C u^{2 +} (a q) (1.0 M) | | C u

0.350

C u^{2 +} (a q) + 2 e^{-} \to C u

- 0.763

Z n^{2 +} (a q) + 2 e^{-} \to Z n

In the reaction Zn +2 $H^{+}$ +2 $C l^{-}$ $⟶$ $Z n^{+} 2$ + 2 $C l^{-}$ + $H_{2}$ the spectator ion

$Z n + 2 H^{+} + 2 C l^{-} - - - - - - - > Z n^{2 +} + 2 C l^{-} + H_{2}$

Z n | Z n^{2 +} (a q) (1.0 M) | | C u^{2 +} (a q) (1.0 M) | | C u

C u^{2 +} (a q) + 2 e^{-} \to C u

Z n^{2 +} (a q) + 2 e^{-} \to Z n

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