$Z n | Z n^{2 +} (C_{1}) | | Z n^{2 +} (C_{2}) | Z n$ ,
for this cell $Δ G$ is negative if:

C_{1} = C_{2}

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C_{1} > C_{2}

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C_{2} > C_{1}

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Both (a) and (c) are correct

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Solution

The correct option is C $C_{2} > C_{1}$
The Nernst equation for the emf of the cell is:

$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0592}{n} l o g \frac{C_{1}}{C_{2}} = 0 - \frac{0.0592}{2} l o g \frac{C_{1}}{C_{2}} .$
The free energy change is negative for this equation.

Hence, the reaction is spontaneous and has a positive value of cell potential. This is possible only when $C_{2} > C_{1} .$

Hence, option C is correct.

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