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Question

Zn|ZnSO4(0.01M)||CuSO4(1.0M)|Cu
The emf of the cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 changed to 0.01 M, the emf changes to E2. From the following, which one is the relationship between E1 and E2?
(Given, RTF=0.059)

A
E1=E2
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B
E1<E2
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C
E1>E2
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D
E2=0E1
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Solution

The correct option is C E1>E2
Zn|ZnSO4(0.01M)||CuSO4(1.0M)|Cu
E1=Ecell2.303RT2F×log(0.01)1
When concentrations are changed
E2=Ecell2.303RT2F×log10.01
i.e., E1>E2

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