wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

ZnSO4 and Pb(NO3)2 have similar powdery white appearance. So, which of the given options help us to identify Zn2+ and Pb2+ when both are treated with NaOH and NH4OH?

A
Formed precipitate Zn(OH)2 is soluble in excess NaOH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Formed precipitate Zn(OH)2 is insoluble in excess NH4OH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Formed precipitate Pb(OH)2 is insoluble in excess NaOH
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Formed precipitate Pb(OH)2 is insoluble in excess NH4OH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Formed precipitate Pb(OH)2 is insoluble in excess NaOH
For ZnSO4NaOHNH4OHColourGelatinous ppt.Gelatinous ppt.SolubilityPrecipitate formed will bePrecipitate formed will be soluble in excess NaOHinsoluble in excess NH4OH

For Pb(NO3)2NaOHNH4OHColourChalky white pptChalky white ppt.SolubilityPrecipitate formed will bePrecipitate formed will be soluble in excess NaOHinsoluble in excess NH4OH

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Lead Ion
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon