Question

$ZnS{O}_4\cdot 7H_{2}O$ loses $H_{2}O$ on exposure to air due to efflorescence property.

If true enter 1, else enter 0.

Answer 1

$ZnS{O}_4.7H_{2}O$ loses $H_{2}O$ on exposure to air due to efflorescence property.
Other examples are as follows:

1. $CaS{O}_4.2H_{2}O$ is a hydrate solid that, in a sufficiently dry environment, will give up its water to the gas phase and form $CaS{O}_4$.
2. $CuS{O}_4.5H_{2}O$ is a blue crystalline solid that when exposed to air, slowly loses water of crystallization from its surface to form a white layer of anhydrous copper(II) sulfate.
3. The correct answer is 1.