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Standard XII

Chemistry

Properties and Reactions of Sodium Peroxide

Zwitter ion c...

Question

Zwitter ion contains:

COOH and -NH

_{3}^{+}

ion

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_{2}

and COO

^{-}

ion

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COO

^{-}

and -NH

_{3}

^{+}

ions

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COO

^{-}

and NH

_{4}

+
ions

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Solution

The correct option is C COO $^{-}$ and -NH $_{3}$ $^{+}$ ions
A zwitter ion is a dipolar ion. It is also known as inner salt.
In the zwitter ion of amino acids, the carboxylic group will be in its basic form $(- C O O^{-})$ and the amino group will be in its acidic form $(- N H_{3}^{+})$ .

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Similar questions

Q. The dissolution of ammonia gas in water does not obey Henry's law. On dissolving, a major portion o fammonia, molecules unite with

H_{2} O

to form

{N H}_{4} O H

molecules.

{N H}_{4} O H

again dissociates into

{N H}_{4}^{+}

and

{O H}^{-}

ions. In solution therefore, we have

{N H}_{3}

molecules,

{N H}_{4} O H

molecules and

{N H}_{4}^{+}

ions and the following equilibrium exist:

{N H}_{3} (g)

(pressure

P

and concentration

c

) Initially

⇌ {N H}_{3} (l) + H_{2} O ⇌ {N H}_{4} O H ⇌ {N H}_{4}^{+} + {O H}^{-}

Let

c_{1}

m o l / L

{N H}_{3}

pass in liquid state which on dissolution in water froms

c_{2}

m o l / L

{N H}_{4} O H

. The solution contains

c_{3}

m o l / L

{N H}_{4}^{+}

ions. The dissociation constant of

{N H}_{4} O H

can be given as:

The reactivity of different nucleophiles

(N H_{2}^{-}, C H_{3} C O O^{-}, O H^{-})

is in the order:

Q. Which is/are not correct variation of indicated properties in

N H_{2}^{-}, N H_{3}

and

N H_{4}^{+}

N H_{3}

cannot release

O H^{-}

ions. Can it be a base?

Q. At

50^{o} C,

the self-ionisation constant (ionic product) of

N H_{3}

is given as,

K_{N H_{3}} = [N H_{4}^{+}] [N H_{2}^{-}] = 10^{- 30} M^{2}

.
How many

N H_{2}^{-}

ions are present per

m m^{3}

of pure liquid ammonia?

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Zwitter ion contains:

The correct option is C COO−and -NH3+ionsA zwitter ion is a dipolar ion. It is also known as inner salt.In the zwitter ion of amino acids, the carboxylic group will be in its basic form (−COO−) and the amino group will be in its acidic form (−NH+3).

The correct option is C COO $^{-}$ and -NH $_{3}$ $^{+}$ ions
A zwitter ion is a dipolar ion. It is also known as inner salt.
In the zwitter ion of amino acids, the carboxylic group will be in its basic form $(- C O O^{-})$ and the amino group will be in its acidic form $(- N H_{3}^{+})$ .