${(\frac{1}{10})}^{0}$ is equal to

$0$

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$\frac{1}{10}$

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$1$

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$10$

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Solution

The correct option is C
$1$

Compute the required value:
From the law of exponents we know that
$a^{0} = 1$
Hence , ${(\frac{1}{10})}^{0} = 1 .$

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Similar questions

From the following place value table, write the decimal number:-

Thousand	Hundred	Tens	Ones	Tenths	Hundredths	Thousandths
$(1000)$	$(100)$	$(10)$	$(1)$	$(\frac{1}{10})$	$(\frac{1}{100})$	$(\frac{1}{1000})$
			$9$	$6$

From the given place value table, write the decimal number.

Thousands	Hundreds	Tens	Ones	Tenths	Hundredths	Thousandths
$(1000)$	$(100)$	$(10)$	$(1)$	$(\frac{1}{10})$	$(\frac{1}{100})$	$(\frac{1}{1000})$
				$8$	$2$	$3$

Find answers to the following. Write and indicate how you solved them.
(i) Is $\frac{5}{9}$ equal to $\frac{4}{5}$ ?
(ii) Is $\frac{9}{16}$ equal to $\frac{5}{9}$ ?
(iii) Is $\frac{4}{5}$ equal to $\frac{16}{20}$ ?
(iv) Is $\frac{1}{15}$ equal to $\frac{4}{30}$ ?

Q. The determinant

A = |\begin{matrix} \sqrt{23} + \sqrt{3} & \sqrt{5} & \sqrt{5} \\ \sqrt{15} + \sqrt{46} & 5 & \sqrt{10} \\ 3 + \sqrt{115} & \sqrt{15} & 5 \end{matrix}|

is equal to is equal to ____________.

Find the value of $x$ so that;
$(i) {(\frac{3}{4})}^{2 x + 1} = {({(\frac{3}{4})}^{3})}^{3}$
$(i i) {(\frac{2}{5})}^{3} \times {(\frac{2}{5})}^{6} = {(\frac{2}{5})}^{3 x}$
$(i i i) {(- \frac{1}{5})}^{20} \div {(- \frac{1}{5})}^{15} = {(- \frac{1}{5})}^{5 x}$
$(i v) \frac{1}{16} \times {(\frac{1}{2})}^{2} = {(\frac{1}{2})}^{3 (x - 2)}$

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1100 is equal to

The correct option is C 1Compute the required value:From the law of exponents we know that a0=1Hence , 1100=1.

${(\frac{1}{10})}^{0}$ is equal to

The correct option is C
$1$

Compute the required value:
From the law of exponents we know that
$a^{0} = 1$
Hence , ${(\frac{1}{10})}^{0} = 1 .$