124amu of P4 will contain________.
Both (B) and (C)
The atomic mass of P = 31amu.
Molecular mass of P4 = 4 × 31 = 124amu.
So, 124 g of P4 contains 1 mole of P4 = NA molecules of Phosphorus=4NA atoms of P(Phosphorus).
Hence, option (D) is correct option.