213 - 657-1 - 213-1- - -

We use law of exponents i.e. (a × b)^m = a^m ×b^m.So, Using the above formula, we get (213 × 657)^ 1 = 213^ 1×657^ 1 .Hence, the answer for the given blank ...

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Byju's Answer

Standard VII

Mathematics

Zero Exponents

213 × 657-1 =...

Question

${(213 \times 657)}^{- 1} = 213^{- 1} \times . . . . . . . . . . . . .$

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Solution

We use law of exponents i.e.
${(a \times b)}^{m} = a^{m} \times b^{m}$ .
So,
Using the above formula, we get
${(213 \times 657)}^{- 1} = 213^{- 1} \times 657^{- 1} .$
Hence, the answer for the given blank is $657^{- 1} .$

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Similar questions

Question 35
$(213 \times 657)^{- 1} = (213)^{- 1} \times$ ___.

Q. Solve the matrix equation

[\begin{matrix} 5 & 4 \\ 1 & 1 \end{matrix}] X = [\begin{matrix} 1 & - 2 \\ 1 & 3 \end{matrix}]

, where X is a 2 × 2 matrix.

Q. Name the property of multiplication of rational numbers illustrated by the following statements:
(i)

\frac{- 5}{16} \times \frac{8}{15} = \frac{8}{15} \times \frac{- 5}{16}

(ii)

\frac{- 17}{5} \times 9 = 9 \times \frac{- 17}{5}

(iii)

\frac{7}{4} \times (\frac{- 8}{3} + \frac{- 13}{12}) = \frac{7}{4} \times \frac{- 8}{3} + \frac{7}{4} \times \frac{- 13}{12}

(iv)

\frac{- 5}{9} \times (\frac{4}{15} \times \frac{- 9}{8}) = (\frac{- 5}{9} \times \frac{4}{15}) \times \frac{- 9}{8}

(v)

\frac{13}{- 17} \times 1 = \frac{13}{- 17} = 1 \times \frac{13}{- 17}

(vi)

\frac{- 11}{16} \times \frac{16}{- 11} = 1

(vii)

\frac{2}{13} \times 0 = 0 = 0 \times \frac{2}{13}

(viii)

\frac{- 3}{2} \times \frac{5}{4} + \frac{- 3}{2} \times \frac{- 7}{6} = \frac{- 3}{2} \times (\frac{5}{4} + \frac{- 7}{6})

Q. (1) Simplify:

(i)

\frac{8}{11} - \frac{7}{11}

(ii)

- \frac{9}{13} + \frac{2}{13}

(iii)

\frac{15}{3} \times \frac{9}{8}

(iv)

14 \div \frac{2}{7}

(v)

\frac{- 12}{0} \times 0

(vi)

\frac{7}{9} \times \frac{3}{5} + \frac{2}{7} \times \frac{7}{5}

(vii)

\frac{5}{3} + \frac{13}{2} \times \frac{2}{15}

Simplify
(i) $2^{\frac{2}{3}} \times 2^{\frac{1}{3}}$
(ii) $2^{\frac{2}{3}} \times 2^{\frac{1}{5}}$
(iii) $7^{\frac{5}{6}} \times 7^{\frac{2}{3}}$
(iv) $(1296)^{\frac{1}{4}} \times (1296)^{\frac{1}{2}}$

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213×657-1=213-1×.............

We use law of exponents i.e. a×bm=am×bm.So, Using the above formula, we get 213×657-1=213-1×657-1.Hence, the answer for the given blank is 657-1.

${(213 \times 657)}^{- 1} = 213^{- 1} \times . . . . . . . . . . . . .$

We use law of exponents i.e.
${(a \times b)}^{m} = a^{m} \times b^{m}$ .
So,
Using the above formula, we get
${(213 \times 657)}^{- 1} = 213^{- 1} \times 657^{- 1} .$
Hence, the answer for the given blank is $657^{- 1} .$