-8 - 27 - -8 - -27- State whether the statement is true T or false F-

Let us considerLHS =√((8 + 27))=√((35)) RHS = √((8)) + √((27))= 2 + 3 0ex0ex= 5On comparing LHS and RHSLHS ≠ RHS√((35)) 5Hence, the answer is false. ...

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Quantitative Aptitude

A.M Greater than or Equal to G.M

√8 + 27 = √8 ...

Question

$\sqrt[3]{(8 + 27)} = \sqrt[3]{(8)} + \sqrt[3]{(27)}$ . State whether the statement is true (T) or false (F).

True

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False

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Solution

The correct option is B False
Let us consider
LHS $= \sqrt[3]{(8 + 27)}$
$= \sqrt[3]{(35)}$
RHS $= \sqrt[3]{(8)} + \sqrt[3]{(27)}$
$= 2 + 3 = 5$
On comparing LHS and RHS
LHS ≠ RHS
$\sqrt[3]{(35)} \neq 5$
Hence, the answer is false.

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(8+27)3=(8)3+(27)3. State whether the statement is true (T) or false (F).

The correct option is B FalseLet us considerLHS =(8+27)3=(35)3 RHS =(8)3+(27)3=2+3=5On comparing LHS and RHSLHS ≠ RHS(35)3≠5Hence, the answer is false.

$\sqrt[3]{(8 + 27)} = \sqrt[3]{(8)} + \sqrt[3]{(27)}$ . State whether the statement is true (T) or false (F).

The correct option is B False
Let us consider
LHS $= \sqrt[3]{(8 + 27)}$
$= \sqrt[3]{(35)}$
RHS $= \sqrt[3]{(8)} + \sqrt[3]{(27)}$
$= 2 + 3 = 5$
On comparing LHS and RHS
LHS ≠ RHS
$\sqrt[3]{(35)} \neq 5$
Hence, the answer is false.